öλÔÓéÀֵǼÈë¿ÚÏÂÔØ

Ãû´Ê½âÊÍ£º£¨Ã¿Ìâ4·Ö£¬3¡¢ ¹²20·Ö£©
£¨1£© ¾­¼ÃѧÖеġ°¾ùºâ¡°º¬Ò壻
£¨2£© ¹©Çó¹æÂÉ£»
£¨3£© ˲ʱ¾ùºâ£»
£¨4£© ÅÁÀÛÍÐ×îÓÅ״̬£»
£¨5£© ¿Æ˹¶¨Àí¡£
4¡¢ ÅжÏÌ⣺£¨ÕýÈ·£«£¬5¡¢ ´íÎó£­6¡¢ £©£¨Ã¿Ìâ4·Ö£¬7¡¢ ¹²20·Ö£©
£¨1£© »¡µ¯ÐÔϵÊý¶ÔÇúÏßÐèÇóÇúÏߵĵ㵯ÐÔϵÊýµÄ¹À¼ÆÔÚ»¡³¤±ä¶ÌºÍ»¡µÄÇúÂʱäСʱ½«µÃµ½¸ÄÉÆ¡£¡­¡­¡­.( )
£¨2£© ij·½°¸µÄ»ú»á³É±¾ÊÇÖ¸£¨3£© ¾ö²ßÕßΪ²ÉÈ¡¸Ã·½°¸¶ø£¨4£© ·ÅÆúµÄËùÓÐÆäËû·½°¸µÄÀûÒæ¡£¡­¡­¡­¡­( )
£¨5£© ÐèÇóÇúÏßбÂÊΪÕýµÄ³äÒªÌõ¼þÊǵ͵µÉÌÆ·ÇÒÊÕÈëЧӦ³¬¹ýÌæ´úЧӦ¡£¡­¡­¡­¡­¡­¡­..( )
£¨6£© µ¼³öÉç»á¸£ÀûÇúÏß±ØÐë×÷³öµÀµÂµÄ¼ÛÖµµÄÅжÏ¡£¡­¡­¡­( )
£¨7£© ijÏîÉú²ú»î¶¯´æÔÚÍⲿ²»£¨8£© ¾­¼Ãʱ£¬£¨9£© Æä²úÁ¿´óÓÚÅÂÀÛÍÐ×îÓŲúÁ¿¡£¡­¡­¡­¡­¡­¡­¡­¡­( )
8¡¢ Ñ¡ÔñÌ⣺£¨µ¥Ñ¡£¬9¡¢ ÿÌâ4·Ö£¬10¡¢ ¹²20·Ö£©
£¨Ò»£©Ä³¸öÏû·ÑÕßµÄÎÞ²îÒìÇúÏßͼ°üº¬ÎÞÊýÌõÎÞ²îÒìÇúÏߣ¬ÒòΪ£¨ £©
A¡¢ ÊÕÈëÓÐʱ¸ß£¬B¡¢ ÓÐʱµÍ£»
C¡¢ ÓûÍûÊÇÎÞÏ޵ģ»
D¡¢ Ïû·ÑÕ߸öÊýÊÇÎÞÏ޵ģ»
E¡¢ ÉÌÆ·µÄÊýÁ¿ÊÇÎÞÏ޵ġ£
£¨¶þ£©Èç¹û¹æÄ£±¨³ê²»±ä£¬µ¥Î»Ê±¼äÀïÔö¼ÓÁË20£¥µÄÀͶ¯Ê¹ÓÃÁ¿£¬µ«±£³Ö×ʱ¾Á¿²»±ä£¬Ôò²ú³ö½«£¨ £©¡£
A¡¢ Ôö¼Ó20£¥£»
B¡¢ ¼õÉÙ20£¥£»
C¡¢ Ôö¼Ó´óÓÚ20£¥£»
D¡¢ Ôö¼ÓСÓÚ20£¥¡£
£¨Èý£©ÔÚ´ÓÔ­µã³ö·¢µÄÖ±Ïߣ¨ÉäÏߣ©ÓëTCÇúÏßµÄÇеãÉÏ£¬AC( )
`£Á¡¢ÊÇ×îС£»
£Â¡¢µÈÓڣͣã»
£Ã¡¢µÈÓÚ£Á£Ö£Ã£«£Á£Æ£Ã£»
£Ä¡¢ÉÏÊö¶¼ÕýÈ·¡£
£¨ËÄ£©Â¢¶Ï¾ºÕù³§É̳¤ÆÚ¾ùºâʱ£¬±ØÈ»ÓУ¨ £©¡£
£Á¡¢³§ÉÌÒ»¶¨ÄÜ»ñµÃ³¬¶îÀûÈó£»
£Â¡¢ÔÚ¾ùºâµãÉÏ£¬Ö÷¹ÛÐèÇóÇúÏßÉϵĵ¯ÐÔ´óÓÚʵ¼ÊÐèÇóÇúÏßÉϵĵ¯ÐÔ£»
£Ã¡¢×ÊÔ´ÔÚ¹ã¸æÖÐÀË·Ñ£»
£Ä¡¢±ß¼Ê³É±¾µÈÓÚʵ¼ÊÐèÇóÇúÏßÖеIJúÉúµÄ±ß¼ÊÊÕÒæ¡£
£¨Î壩ÔÚÍêÈ«¾ºÕùµÄ²úÆ·ºÍÒªËØÊг¡Öо­ÓªµÄ³§ÉÌ£¬Æä×ÜÀûÈóÂÊ´ïµ½×î´óµÄÌõ¼þΪ£¨ £©
£Á¡¢£Ðx=MCx,ÇÒMCxÉÏÉý£»
£Â¡¢£Í£Ð£Ða/Pa=£Í£Ð£Ðb/Pb;
C¡¢£Í£Ð£Ða/Pa=£Í£Ð£Ðb/Pb£½£±£¯£Í£Ãx
;
D¡¢£Í£Ð£Ða/Pa=£Í£Ð£Ðb/Pb£½£±£¯£Í£Ãx
;£½£±£¯£Ðx
£¨É賧ÉÌÒÔÒªËØa¡¢bÉú²úÉÌÆ·x£©
11¡¢ ¼ò´ðÌ⣺£¨Ã¿Ìâ5·Ö£¬12¡¢ ¹²20·Ö£©
£¨1£© °´ÕÕÐèÇó¶¨Àí£¬£¨2£© ÉÌÆ·µÄÐèÇóÁ¿ÊÇÓëÆä¼Û¸ñ³Ê·´·½Ïò±ä¶¯µÄ£¬£¨3£© µ«Êг¡µÄʵ¼ÊÇé¿öÊÇ£ºÉÌÆ·ÐèÇóÔö¼Ó£¬£¨4£© ¼Û¸ñÉÏÉý£¬£¨5£© ÐèÇó¼õÉÙ£¬£¨6£© ¼Û¸ñϽµ£¬£¨7£© ÐèÇóÓë¼Û¸ñÊdzÊÕý·½Ïò±ä¶¯µÄ¡£ÕâÊÇΪʲô£¿Çë˵Ã÷ÀíÓÉ¡£
£¨8£© µ±éÙ×Ó²úµØÊÜÔÖʱ£¬£¨9£© Èç¹û¶ÔéÙ×ÓµÄÐèÇóԽȱµ¯ÐÔ£¬£¨10£© ÄÇô¶ÔéÙ×ӵļ۸ñµÄÓ°ÏìÒ²¾ÍÔ½´ó¡£ÕâÊÇΪʲô£¿
£¨11£© ÆÚ»õÊг¡ÎªÊ²Ã´¿ÉÒÔ¼õÉÙÖëÍø²¨¶¯£¿
£¨12£© Ϊʲôµ±¼Û¸ñ¸ßÓÚ×îµÍƽ¾ù¿É±ä³É±¾Ê±£¬£¨13£© ÍêÈ«¾ºÕùÆóÒµµÄ¹©¸øÇúÏßÓë±ß¼Ê³É±¾ÇúÏßÏàͬ£¨14£© £¿
13¡¢ ¼ÆËãÌ⣺£¨Ã¿Ìâ5·Ö£¬14¡¢ ¹²20·Ö£©
£¨1£© ¼ÙÉèijÊг¡ÓÉ¡°¸öÈË1¡°ºÍ¡°¸öÈË2¡°×é³É£¬£¨2£© ËûÃǶÔÉÌÆ·xµÄÐèÇóº¯Êý·Ö±ðΪ£º
D1£½(Pr+K1Y1)/Px
D2£½K2Y2/Px
(a) ÇóÉÌÆ·xµÄÊг¡ÐèÇóº¯Êý£»
£¨b£©¼ÆËã¶ÔÉÌÆ·xµÄÊг¡ÐèÇó¼Û¸ñµ¯ÐÔºÍÐèÇ󽻲浯ÐÔ¡£
£¨c£©Éèy1¡¢y2·Ö±ðΪ¡°¸öÈË1¡°ºÍ¡°¸öÈË2¡°µÄÊÕÈë¡£ÔÚ×ÜÊÕÈë²»±äÏà(y)µÄÇé¿öÏ£¬Í¨¹ýÊÕÈëÔÙ·ÖÅäʹ¡°¸öÈË2¡°µÄ²¿·ÖÊÕÈëתÒƵ½¡°¸öÈË1¡°»á¶ÔÉÌÆ·xµÄÐèÇó²úÉúʲôӰÏ죿
(¶þ)¼Ù¶¨Ä³Ïû·ÑÕßµÄЧÓú¯ÊýΪu=xy4,Ëû»á½«ÊÕÈëµÄ¶àÉÙÓÃÓÚÉÌÆ·y ÉÏ£¿
£¨3£© ÍêÈ«¾ºÕù³§É̵ĶÌÆڳɱ¾º¯ÊýSTC=0.04Q3-0.8Q2+10Q+5£¬£¨4£© ÊÔÇó³§É̵ĶÌÆÚ¹©¸øº¯Êý¡£
£¨5£© ij¹«Ë¾Ãæ¶ÔÒÔÏÂÁ½¶ÎÐèÇóÇúÏß
p=25-0.25Q(µ±²úÁ¿Îª0¨D¨D20ʱ)
p=35-0.75Q(µ±²úÁ¿³¬¹ý20ʱ)
¹«Ë¾×ܳɱ¾º¯ÊýΪ£ºTC£½200£«5Q£«0.255Q2.
(1) ˵Ã÷¸Ã¹«Ë¾ËùÊôÐÐÒµµÄÊг¡½á¹¹ÊÇʲôÀàÐÍ£¿
(2) ¹«Ë¾µÄ×îÓż۸ñºÍ²úÁ¿ÊǶàÉÙ£¿ÕâʱÀûÈ󣨿÷Ë𣩶à´ó£¿
(3) Èç¹û³É±¾º¯Êý¸ÄΪTC2£½200£«8Q£«0.25Q2,×îÓż۸ñºÍ²úÁ¿ÊÇ