n CO2µÄCV,m=(20.96+0.0293T/K) J·K-1·mol-1¡£¼Ù¶¨ÆøÌå·þ´ÓÀíÏëÆøÌå·½³Ì¡£¼ÆËãÖÕ̬ʱÑõµ¯µÄζȼ°Ñ¹Á¦¡£
n [´ð] ·´Ó¦ºãÈݾøÈȽøÐУ¬
n ΔrH(T)=ΔrU(T)+ΔnRT
n ¹ÊΔU ==[-280 332.9+0.01465(T/K)2+20.96(T/K)-7606.5]J = 0
n ½âµÃT =3775 K,
n p = 850 kPa
n Àý2
n py,298 Kʱ£¬ÒÒ´¼(l)µÄDcHmy = -1366.9 kJ·mol-1, CO2(g)ºÍH2O(l)µÄDfHmy·Ö±ðΪ-393.5ºÍ-285.9 kJ·mol-1¡£
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n £¨2£©¼ÆËãC2H5OH(l)µÄ±ê׼Ħ¶ûÉú³ÉÈÈ¡£
n £¨3£©Èô2.0 mol C2H5OH(l)ÔÚÑõµ¯ÖÐȼÉÕ£¬ÆäÈÈЧӦQVΪ¶àÉÙ£¿
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n »òÕß˵£º“²»¿ÉÄÜÉè¼Æ³ÉÕâÑùÒ»ÖÖ»úÆ÷£¬ÕâÖÖ»úÆ÷ÄÜÑ»·²»¶ÏµØ¹¤×÷£¬Ëü½ö½ö´Óµ¥Ò»ÈÈÔ´ÎüÈ¡ÈÈÁ¿±äΪ¹¦£¬¶øÃ»ÓÐÈÎºÎÆäËû±ä»¯¡£”
n “µÚ¶þÀàÓÀ¶¯»úÊDz»¿ÉÄÜÔì³ÉµÄ¡£”
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n ¿ÉÄæ¿¨Åµ»ú£º
h = 1£(T1/ T2) £¨ÀíÏë»òʵ¼ÊÆøÌ壩
n Èô¿ÉÄæ¿¨Åµ»úµ¹¿ª£¬ÖÆÀä»úÀ䶳ϵÊý£º
b = Q¢1/(-W) = T1 / ( T2£T1)
n ÈÈ»úЧÂÊ£ºh £ 1£(T1/ T2)
n ¶Ô¿ÉÄæ¿¨ÅµÑ»·£¬ÓÐ(Q1/ T1) + (Q2 / T2) = 0
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¡Ó(dQr / T ) = 0
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n »ý·ÖÖµ∫AB dQr / T ±íʾ´ÓA® BÌåϵij¸ö״̬º¯ÊýµÄ±ä»¯Öµ¡£
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n µ±ÌåϵµÄ״̬ÓÉA±äµ½Bʱ£¬ìغ¯ÊýµÄ±ä»¯Îª£º
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n Èç¹û±ä»¯ÎÞÏÞС£¬¿Éд³É(״̬º¯ÊýµÄ) ΢·ÖÐÎʽ£º
d S = dQr / T
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n “¹ÂÁ¢ÌåϵÖеĹý³Ì×ÜÊÇ×Ô·¢µØÏòìØÖµÔö¼ÓµÄ·½Ïò½øÐС£” — ìØÔö¼ÓÔÀí
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n “Ò»ÇÐ×Ô·¢¹ý³ÌµÄ×ÜìØ±ä¾ù´óÓÚÁã” — ìØÔö¼ÓÔÀí
n ÉÏʽÖУ¬QΪÌåϵµÄÈÈЧӦ QÌå
DS»· =£S dQ/ T»·
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£¨DS£©T = nR ln(V2/V1) = nR ln(P1/P2)
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(DSmix ) T = £R [nA lnx A + nB lnxB ]
n µÈѹ¹ý³Ì£º (DS)P = òT1T2 (Cp/T)dT
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n µÈÈݹý³Ì£º (DS)v = òT1 T2 (Cv /T)dT
ÈôCvΪ³£Êý (DS)v = Cv ln (T2/T1)
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DS = Cv ln (T2/T1) + nRln(V2/V1)
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